SSC CHSL 2025 PYQ — Question 62

SSC CHSL - 28 Nov 2025 - Shift 1 • Quantitative Aptitude • Q62

A circular sprinkler is placed inside a triangular garden with sides 13 m, 14 m, and 15 m. What is the radius of the sprinkler if it touches all three sides of the triangle?

Show answer & explanation

Correct answer: A

Explanation

Has been given :

Sides of triangle = 13 m, 14 m, 15 m

According to the formula:

Radius r = area / semiperimeter

Semiperimeter s = (13 + 14 + 15) / 2= 21

Area = √[s(s − a)(s − b)(s − c)]

= √[21(21 − 13)(21 − 14)(21 − 15)]

= √[21 × 8 × 7 × 6]

= √7056

= 84

r = area / perimeter = 84 / 21 = 4

Radius of sprinkler = 4 m