A circle is inscribed within a right triangle. Considering that the lengths of the two legs measure 6 cm and 8 cm, what is the radius of the inscribed circle?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e. 2 cm.
Hypotenuse = √(62 + 82) = √(36 + 64) = √100 = 10 cm
Area = (1/2) × 6 × 8 = 24 cm2
Semiperimeter = (6 + 8 + 10)/2 = 24/2 = 12 cm
Inradius = Area/Semiperimeter = 24/12 = 2 cm