A circle is inscribed in triangle ABC, touching AB, BC and AC at the points P, Q and R , respectively. If AB - BC = 4 cm, AB - AC = 2 cm and the perimeter of triangle ABC = 32 cm, then PB + AR is equal to:
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Correct answer: D
Explanation
The correct answer is option 4 i.e. (38/3) cm.
Given: AB - BC = 4 cm, AB - AC = 2 cm and perimeter = 32 cm
We can write:
a + b + c = 32 ............ (1)
c - b = 2 ............ (2)
c - a = 4 ............ (3)
Adding all 3 equations:
⇒ 3c = 38
⇒ c = 38/3