A circle is inscribed in △PQR, touching the sides QR, PR and PQ at the points A, U and T, respectively PQ = (QR + 5)cm, PQ = (PR + 2)cm. If the perimeter of △PQR is 32 cm, then PR is equal to:
Show answer & explanation
Correct answer: B
Explanation
The correct answer is option 2 i.e. 11 cm
According to the question,
Let PR = x then PQ = x + 2
QR = x + 2 - 5 = x - 3.
Perimeter of a △PQR = x - 3 + x + 2 + x = 32
3x - 1 = 32
x = 11
PR = x = 11