A circle is inscribed in a triangle ABC. It touches sides AB, BC and AC at point R, P and Q. respectively. If AQ = 3.5 cm, PC = 4.5 cm, and BR = 7 cm, then the perimeter ( in cm) of the triangle ABC is :
Show answer & explanation
Correct answer: D
Explanation
The correct answer is option 4 i.e. 30
AR = AQ, BR = BP and QC = CP
AQ = 4.5 cm and PC = 5.5 cm and BR = 6 cm
AQ = AR = 4.5 cm and PC = QC = 5.5 cm
BR = BP = 6 cm
Perimeter of triangle = AR + BR + BP + PC + CQ + AQ = 4.5 + 6 + 6 + 5.5 + 5.5 + 4.5 = 32 cm