A circle is inscribed in a triangle ABC. It touches sides AB, BC and AC at points P, Q and R respectively. If BP = 9 cm, CQ = 10 cm and AR = 11 cm, then the perimeter (in cm) of the triangle ∆ABC is
Show answer & explanation
Correct answer: A
Explanation
Correct Answer is option 1 i.e. 60
|
Concept |
Understanding |
Application |
|
Two tangents drawn from external point on the circle are equal. |
Given: BP = 9 cm, CQ = 10 cm and AR = 11 cm
|
Hence, AP = AR = 11 cm BP = BQ = 9 cm And CQ = CR = 10cm ∴ Perimeter of triangle = 11 + 11 + 9 + 9 + 10 + 10 = 60 cm |
