A circle is centred at O. Two tangents AP and AQ are drawn from an external point A. If ∠POQ = 118o, then ∠PAQ is equal to:
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e 62o
|
Understanding Tricks |
|
Application According to figure
|
|
Here we have Quadrilateral APOQ So the sum of all angle = 360 |
|
We know the radius of the circle make 90 on the tangent So ∠OPA = ∠OQA = 90 |
|
Now ∠POQ + ∠OPA + ∠OQA + ∠PAQ = 360 118 + 90 + 90 + ∠PAQ = 360 ∠PAQ = 360 - 298 ∠PAQ = 62 |
