A chord of length 40 cm is drawn in a circle having a diameter of 50 cm. What is the minimum distance of the other parallel chord of length 30 cm in the same circle from the 40 cm long chord?
Show answer & explanation
Correct answer: C
Explanation
The correct answer is Option 3 i.e. 5 cm.
In triangle AOM,
AO2 = AM2 + OM2
⇒ 252 = 202 + OM2
⇒ 625 - 400 = OM2
OM = 15 cm
In triangle CON,
CO2 = CN2 + ON2
⇒ 252 = 152 + OM2
⇒ 625 - 225 = OM2
OM = 20 cm
So, the distance between the chords MN = 20- 15 = 5 cm