SSC Selection Post 2025 PYQ — Question 38

SSC Selection Post - Matriculation Level - 30th July 2025 - Shift 1 • Quantitative Aptitude • Q38

A chord of length 12 cm is 5 cm away from the center. Find the radius.

Show answer & explanation

Correct answer: B

Explanation

Length of the chord = 12 cm

Half of the chord = 12/2 = 6 cm

Distance of the chord from the center = 5 cm

Now, in the right-angled triangle,

Radius² = 6² + 5²

= 36 + 25

= 61

Radius = √61 cm