SSC MTS 2026 PYQ — Question 13

SSC MTS - 17 Feb 2026 - Shift 3 • Quantitative Aptitude • Q13

A car leaves town A for town B (distance 320 km) at 7:00 a.m. with a speed of 64 km/h. A truck leaves town B for A 30 minutes later and travels at 56 km/h. At what time (clock) do they meet, and how far from A is the meeting point? (Round decimal values to two places)

Show answer & explanation

Correct answer: B

Explanation

Given:

Distance from A to B = 320 km

Speed ​​of the car = 64 km/h

Speed ​​of the truck = 56 km/h

The truck starts 0.5 hours later.

According to the formula:

Distance = Speed ​​× Time

Let's assume the car travels for *t* hours.

Distance covered by the car = 64*t*

Distance covered by the truck = 56(*t* − 0.5)

Total distance:

64*t* + 56(*t* − 0.5) = 320

64*t* + 56*t* − 28 = 320

120*t* = 348

*t* = 2.9 hours

Time = 7:00 + 2.9 hours

= 7:00 + 2 hours 54 minutes

= 9:54 AM

Distance from A = 64 × 2.9 = 185.6 km

Time = 9:54 AM, Distance = 185.60 km