A can finish a piece of work in 33 days and B can do the same work in one-third the time taken by A. Working together how much of the same work can they both finish in six days?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e. .
Time taken by B alone = 1/3 × 33 = 11 days
Let the total work to be done (LCM of 33, 11) be 33 units.
Efficiency of A = 33/33 = 1 unit/day
Efficiency of B = 33/11 = 3 units/day
Working together, work done in 6 days = 6 × 4 = 24 units
Required answer = 24/33 = 8/11