A can do a work in 10 days. He worked for 6 days and left the work. The remaining work was done by B in 8 days .In how many days can B alone to 65% of the work?
Show answer & explanation
Correct answer: D
Explanation
The correct answer is option 4 i.e. 13.
Let total work = LCM of 10 and 20 = 20 units
Efficiency of A = 20/10 = 2 units/day
Efficiency of B = 20/20 = 1 unit/day
A's 6-day work = 6 × 2 = 12 units
Remaining work = 20−12 =8 units
B does 8 units in 8 days ⇒ B’s efficiency = 1 unit/day
65% of 20 units = (65/100) × 20 = 13 units
B does 1 unit/day ⇒ Time = 13/1 = 13 days