A can do a piece of work in 28 days. B is 68% more efficient than A. Find the number of days taken by B to do the same piece of work.
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e. 50/3 days.
A can do the work I 28 days , A's efficiency is 1/ 28 of the work per day.
B is 68% more then A .
68 % of A's efficiency = 0.68 × 1/2
⇒ 0.68 / 28 = 17 / 700
B's efficiency = 1/28 + 17 / 700
⇒ 25 / 700 + 17 / 700
⇒ 42 / 700
⇒ 3 / 50
B's efficiency is 3/ 50 of the work per day, the number of days B takes is = 1 / (3/50)
⇒ 50 / 3days