A can do a piece of work alone in 40 days. A and B together can do the same work in 10 days. C is 50% less efficient than B. In how many days can A and C together complete the same work?
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e. 16 days.
Given:
A can do a piece of work alone in 40 days.
A and B together can do the same work in 10 days.
C is 50% less efficient than B
Calculations:
Let the total work be 40 units (LCM of 10 and 40)
Efficiency of A = 40/40 = 1
Efficiency of A and B = 40/10 = 4
Efficiency of B = 4 - 1 = 3
Efficiency of C = 50% of 3 = 1.5
Required time = 40/2.5 = 16 days