A can do a certain work in 40 days. B is 60% more efficient than A. Both work together for 10 days. C alone completes the remaining work in days. Working together, B and C can complete 44% of the original work in:
Show answer & explanation
Correct answer: B
Explanation
The correct answer is Option 2 i.e. 6 days.
A can do full work in 40 days
A’s 1 day work = 1/40
B is 60% more efficient
B’s 1 day work = 1/40 × 160% = 1/25
A + B work 10 days , Work done = (1/40 + 1/25) × 10 = 13/20
Remaining work = 1−13/20 = 7/20
C completes 7/20 work in 10.5 days , C’s 1 day work = 7/20 ÷ 10.5 = 1/30
B + C = 1/25 + 1/30 = 11/150
Time to do 44% work = 44/100 ÷ 11/150 = 6 days