A can complete a work in 11 days. B is 25% more efficient than A and C is 50% efficient than B. Working together A, B and C will complete the same work
Show answer & explanation
Correct answer: B
Explanation
The correct answer is option 2 i.e. 4 days
Let the efficiency of A be 8 units/day.
Efficiency of B = 25% more than A = 8 × 1.25 = 10 units/day.
Efficiency of C = 50% of B = 10 × .5 = 5 units/day.
Total work = 8 × 23/2 = 92 units.
Time taken by them to complete the work together = 92/(8 + 10 + 5) = 92/23 = 4 days.