A can complete a piece of work in 25 days while B can complete the same work in 30 days. They work on alternate basis, starting with A. Both A and B follow this pattern for 5 days and then A leaves the work. In how many days will B finish the remaining work?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is Option 1 i.e 24(2/5)
A can complete a piece of work in 25 days while B can complete the same work in 30 days.
L.C.M(25, and 30) = 150
The efficiency of A = 150/25 = 6 units
The efficiency of B = 150/30 = 5 units
A work for 1st day = 6 units
B work for 2nd day = 5 units
A work for 3rd day = 6 units
B work for 4th day = 5 units
A work for 5th day = 6 units
Total work in 5 days = 28 units
Remaining work = 150 - 28 = 122
B finish the remaining work in = 122/5 = 24(2/5) days