SSC CHSL 2025 PYQ — Question 70

SSC CHSL - 18 Nov 2025 - Shift 2 • Quantitative Aptitude • Q70

A bus starts 30 minutes late and to reach its destination 150 km away on time, it increases its speed by 25 km/h. What is the usual speed of the bus?

Show answer & explanation

Correct answer: B

Explanation

Given:

Distance = 150 km

Bus is 30 minutes late

Speed ​​increase = 25 km/h

Formula:

Time = Distance / Speed

Let the bus's usual speed = x km/h

Normal time = 150 / x

New speed = (x + 25) km/h

New time = 150 / (x + 25)

Time difference = 30 minutes = 1/2 hour

150/x − 150/(x + 25) = 1/2

150(x + 25) − 150x / x(x + 25) = 1/2

3750 / x(x + 25) = 1/2

x(x + 25) = 7500

x² + 25x − 7500 = 0

(x + 100)(x) − 75) = 0

x = 75 km/h