A beaker contains a mixture of two liquids X and Y in the ratio 5 : 3. When 6 litres of the mixture is drawn off and then replaced with Y, the ratio of X and Y becomes 5 : 7. How many litres of liquid X was contained in the beaker initially?
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e. 11.25.
Calculations:
Ratio of X and Y initially = 5x : 3x ---- (1)
After replacement = 5x : 7x ---- (2)
The quantity remains the same, multiply eq(1) with 3 and eq(2) with 2
Quantity of X initially = 15x
After replacement, quantity of X = 10x
According to the question;
⇒ 15x - 10x = 6
⇒ 5x = 6
Thus, 15x = 18
Now quantity is divided in the ratio of 5 : 3
⇒ 8 → 18
Hence, quantity of X initially = 5 × 2.25 = 11.25