A, B, and C can individually complete a task in 24 days, 16 days, and 32 days respectively. If A and C start the work and worked for 6 Days and left, then the number of days required by B to complete the remaining task is:
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e 9
Let the number of units of work be LCM (24, 16, 32) = 96 units.
Number of units of work completed by A in one day = 96 / 24 ⇔ 4 units
Number of units of work completed by B in one day = 96 / 16 ⇔ 6 units
Number of units of work completed by C in one day = 96 / 32 ⇔ 3 units
A & C worked for 6 days ⇒ 6(4 + 3) = 42 units
Number of units left ⇒ 96 - 42
⇒ 54 units
B would take the number of days to complete the work = 54 / 6
⇒ 9 days