A, B and C can finish a work in 15 days working alternately in the same order. The efficiency of A is the same as that of B, and the efficiency of C is equal to that of A. In how many days will the work be finished if they work alternately in the order C, A and B?
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e. 15.
Given that
Efficiency of A = B = C = 1 unit (let)
Hence 3 units of work will be done in 3 days by A, B, and C in this order
⇒ The total work = Work done in 15 days = 15 units
Hence C, A, and B, in this order will do 3 units in 3 days
Hence, they will complete 15 units of work in 15 days