A, B and C can do a piece of work in 11 days, 20 days and 55 days respectively. If B works daily and is supported by A and C on alternate days beginning with A, then in how many days will the work be finished?
Show answer & explanation
Correct answer: B
Explanation
The correct answer is 2 i.e.
Concept Used:
Explanation:
Let the total work done be LCM of (11, 20, 55) = 220 units.
Now, efficiency of A =
Efficiency of B =
Efficiency of C =
According to the given question, work done is as follows
(B + A) + (B + C) + (B + A) + (B + C)....so on
So, work done in 2 days = (11 + 20) + (11 + 4) = 46 units
Then, work done in (2 × 4) = 8 days = (46 × 4) = 184 units
Now (B + A) work for 1 day, work done in 9 days = 184 + 31 = 215 units
Remaining work to be done = 220 - 215 = 5 units
So, (B + C) complete 15 units in one day, they will complete 5 units in days.
Hence the total time taken to complete the whole work is days.