A,B and C can do a piece of work in 30 days, 40 days, and 50 days, respectively. Beginning with A, if A, B and C do the work alternatively, then in how many days will the work be finished?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e. 38
Given that
A,B and C can do a piece of work in 30 days, 40 days and 50 days, respectively
Total work = 600
The efficiency of A = 600/30 = 20
The efficiency of B = 600/40 = 15
The efficiency of C = 600/50 = 12
Beginning with A, if A, B and C do the work alternatively,
In 3 days, (20 + 15 + 12 = 47) work will be completed
In (3 × 12 = 36) days, (47 × 12 = 564) work will be completed
Now, Remaining work (600 - 564 = 36) will be completed in (2 + (1/12)) days
Hence, the total work completed in = 36 + 2 + (1/12) days = 38 days