A, B and C can do a piece of work in 11 days, 20 days and 55 days respectively. How soon can the work be done if A works with B on first day, A works with C on second day and so on?
Show answer & explanation
Correct answer: C
Explanation
The correct answer is Option 3 i.e. 8 days.
A, B, and, C can do a piece of work in 11 days, 20 days, and 55 days respectively
L.C.M (11, 20, and 55) = 220
The efficiency of A = 220/11 = 20 units
The efficiency of B = 220/20 = 11 units
The efficiency of C = 220/55 = 4 units
A and B work on first day = 20 + 11 = 31 units
A and C work on second day = 20 + 4 = 24 units
Work done in 2 days
⇒ 2 days = 55 units (multiplied by 4)
⇒ 2 × 4 days = 55 × 4 units
⇒ 8 days = 220 units
So, the work will be completed in 8 days