A and B working separately can complete a piece of work in 10 and 16 days, respectively. If they work for a day alternately, with A beginning the work, in how many day(s) will the work be completed?.
Show answer & explanation
Correct answer: B
Explanation
The correct answer is Option 2 i.e.
Given:
Time taken by A alone = 10 days
Time taken by B alone = 16 days
Explanation:
Time taken by A to complete the work = 10 days
So, part of work done by A in 1 day = 1/10
Time taken by B to complete the work = 16 days
So, part of work done by B in 1 day = 1/16
Now, the part of work done by (A + B) in 2 days = (1/10 + 1/16) = 13/80
Now, let the total work to be done by (A + B) be 80 units.
Efficiency of A = 8 units/day
Efficiency of B = 5 units/day
The work done by (A + B) in 2 days is 13 units.
Now, work done by (A + B) in (2 × 6) days is (13 × 6) units
So, work done by (A + B) in 12 days is 78 units.
Now A will come to work and complete the remaining 2 units work in 2/8 days = 1/4 days.
So, the total work will be done in days.