A and B together can finish a work in 18 days, B and C in 24 days, and C and A in 36 days. In how many days can B alone complete the work?
Show answer & explanation
Correct answer: A
Explanation
a + b = 1/18
b + c = 1/24
c + a = 1/36
Adding the three equations -
2(a + b + c) = 1/18 + 1/24 + 1/36
= (4 + 3 + 2)/72
= 9/72
= 1/8
a + b + c = 1/16
b = (a + b + c) − (a + c)
= 1/16 − 1/36
= (9 − 4)/144
= 5/144
Time taken by B to complete the work -
= 144/5
= 28.8 days