A and B together can do a piece of work in 8 days. B and C can do it in 12 days, and C and A can do it in 16 days.
In how many days can A alone do the work?
Show answer & explanation
Correct answer: A
Explanation
A + B = 1/8, B + C = 1/12, C + A = 1/16
(A + B) + (B + C) + (C + A) = 2(A + B + C)
1/8 + 1/12 + 1/16 = (6 + 4 + 3) / 48 = 13/48
2(A + B + C) = 13/48
A + B + C = 13/96
A = (A + B + C) − (B + C)
= 13/96 − 1/12
= 13/96 − 8/96
= 5/96
Time = 1 / (5/96) = 96/5 = 19.2 days