A and B together can do a piece of work in 24 days. A alone can do this work in 40 days. In how many days can B alone do this work?
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e. 60 days.
Calculations:
Total work (LCM of 24 and 40) = 120 units
Efficiency of A + B = 120/24 = 5
Efficiency of A = 120/40 = 3
Efficiency of B = 5 - 3 = 2
Hence, the number of days taken by B to complete the work = 120/2 = 60 days