A and B together can do a piece of work in 50 days. If A is 40% less efficient than B, in how many days can A working alone complete 60% of the work?
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e. 80
Given:
(A + B) can together complete the work in 50 days.
A is 40% less efficient than B
Concept Used:
Total work = Efficiency × total time
Explanation:
Let the efficiency of B be 5x, then efficiency of A = 60% of 5x = 3x
Total efficiency of (A + B) = 8x
Total work = 8x × 50 = 400x
Amount of work A has to complete = 60% of 400x = 240x
Time taken by A alone = 240x/3x = 80
Hence, the time taken by A to complete 60% of the total work is 80 days.