SSC CHSL 2023 PYQ — Question 65

The correct answer is option 1 i.e. 3$\frac3{5}$ days.

A and B can finish the work in 6 days and 4 days, respectively.

Let the total work = 12 (LCM of 6 and 4)

Efficiency of A = 12/6 = 2

Efficiency of B = 12/4 = 3

Work done by A in 2 days = 2 × 2 = 4

Remaining work = 12 - 4 = 8

Time required for A and B to do remaining work = 8/(2 + 3) = 8/5 = $1\frac{3}{5}$ days

Total time = 2 + $1\frac{3}{5}$ = $3\frac{3}{5}$ days

Therefore, the time required to finish the work is $3\frac{3}{5}$ days.