A and B can complete a task in 25 days. B alone can complete 
% of the same task in 15 days. In how many days can A alone complete (4/15)th of the same task?
Show answer & explanation
Correct answer: C
Explanation
Correct Answer is option 3 i.e. 15
|
Concept |
Understanding |
Application |
Fair calculation |
|
Work efficiency |
A and B can complete a task in 25 days B alone can complete 100/3% of the same task in 15 days. Hence, B alone will complete the work in 45 days |
1/A + 1/45 = 1/25 1/A = 4/225 A alone will complete the work in 225/4 days. A alone will complete 4/15th of the same task = (225/4) × 4/15 = 15 days |
1/A + 1/45 = 1/25 1/A = 1/25 – 1/45 1/A = [9 – 5]/225 1/A = 4/225 |