A and B can complete a piece of work in 10 and 16 days respectively. A begins to do the work and they work alternatively one at a time for one day each. The whole work will be completed in :
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e.
Calculations:
Total work (LCM of 10 and 16) = 80 units
Efficiency of A = 80/10 = 8
Efficiency of B = 80/16 = 5
Work done in 2 days, if they work alternatively starting with A
⇒ 2 days = 13 unit work
⇒ 12 days = 78 unit work
Remaining work is completed by A = 2/8 = 1/4
Hence total time = 12 + 1/4 = 12(1/4) days