SSC MTS 2026 PYQ — Question 5

SSC MTS - 18 Feb 2026 - Shift 2 • Quantitative Aptitude • Q5

A and B can complete a job together in 18 days; A alone takes 30 days. They worked together some days, then A left; B finished the rest. The total time was 20 days. For how many days did they work together?

Show answer & explanation

Correct answer: A

Explanation

Given:

A + B = 18 days

A = 30 days

Total time = 20 days

According to the formula:

Work Rate = 1 / Time

Rate of (A + B) = 1/18

Rate of A = 1/30

Rate of B = 1/18 − 1/30

= (5 − 3)/90 = 2/90 = 1/45

Let the time worked together be x days.

x(1/18) + (20 − x)(1/45) = 1

x/18 + (20 − x)/45 = 1

Multiplying by the LCM (90):

5x + 2(20 − x) = 90

5x + 40 − 2x = 90

3x = 50

x = 16⅔ days