SSC MTS 2022 PYQ — Question 61

The correct answer is option 3 i.e. 7.2 sec.

Distance = 200 m 

Speed = 100 km/hr 

Distance = speed × time

Speed(in m/s) = Speed(in km/h) $\times {5 \over 18}$

Speed of train(in m/s) = $100 \times {5 \over 18}$

Required time = $200 \over {100 \times{5 \over 18}}$= ${2 \times 18}\over 5$ = 7.2 sec

Hence the required time to pass a man standing near the railway line is 7.2 sec.