SSC MTS 2026 PYQ — Question 18

SSC MTS - 4 Feb 2026 - Shift 3 • Quantitative Aptitude • Q18

A 200 m long train crosses a man standing on a platform in 10 seconds, and another train of the same length coming from the opposite direction in 8 seconds. Find the speed of the second train.

Show answer & explanation

Correct answer: C

Explanation

Length of the first train = 200 m
Time taken to cross the person = 10 s
Length of the second train = 200 m
Time taken to cross each other = 8 s
Speed ​​of the first train = 200 / 10 = 20 m/s
Relative speed of both trains = (200 + 200) / 8 = 50 m/s
Speed ​​of the second train = 50 − 20 = 30 m/s
In km/h = 30 × 18 / 5 = 108 km/h