A 10-litre solution of milk and water contains 8 litres of milk. 2 litres of the solution is replaced by pure milk and mixed. The process is repeated two more times. How much milk (in litres) is present in the mixture so obtained?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e. 8.976.
Initially ratio of milk and water = 8 : 2 = 4 : 1
In 2 litres of mixture, Quantity of water = 2 × 1/5 = 0.4 liters
Water after 1st replacement/Initial water = 0.4/2 = 1/5
Initial water Final water
1st replacement 5 : 4
2nd replacement 5 : 4
3rd replacement 5 : 4
125 : 64
125 units = 2 litres
⇒ 64 units = (2/125) × 64 = 1.024 litres
Final milk quantity = 10 - 1.024 = 8.976 litres