9 years ago, the average age of a family of five members was 33 years. Now, three new members join whose ages are in ascending order with consecutive gaps of 8 years. If the present average age of the family is the same as it was 9 years ago, what is the age (in years) of the eldest new member?
Show answer & explanation
Correct answer: B
Explanation
Correct Answer is option 2 i.e. 26
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Understanding |
Application |
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Suppose the age of youngest new member = x Then, Age of middle member = x + 8 And Age of eldest member = x + 16 |
9 years ago, The total age of 5 members = 33 × 5 = 165 Total age of 8 members at present = 33 × 8 = 264 And Total age of 5 members at present = 165 + 45 = 210 Total age of 3 new members at present = 264 – 210 = 54 According to question: x + x + 8 + x + 16 = 54 ⇒ 3x + 24 = 54 ⇒ 3x = 30 ⇒ x = 10 Hence, age of eldest new member = 10 + 16 = 26 years |