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SSC GD 2025 PYQ — Question 41

SSC GD Const 2025 (English) - 04 Feb 2025 - Shift 1 • Quantitative Aptitude • Q41

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[(48÷8)×{497+404×(7−3)}]\left [ \left ( 48\div 8 \right )\times \left\{ \frac{49}{7}+\frac{40}{4}\times \left ( 7-3 \right )\right\} \right ] = ?

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Correct answer: D

Explanation

The correct answer is Option 4 i.e. 282.

 [(48÷8)×{497+404×(7−3)}]\left [ \left ( 48\div 8 \right )\times \left\{ \frac{49}{7}+\frac{40}{4}\times \left ( 7-3 \right )\right\} \right ] = ?

= 6 × {7 + 10 × 4}

= 6 × 47

= 282