423+4423+44423+444423=?4\frac{2}{3} + 44\frac{2}{3} + 444\frac{2}{3} + 4444\frac{2}{3} = ?432+4432+44432+444432=? A4936234936\frac{2}{3}493632 B4938134938\frac{1}{3}493831 C4935234935\frac{2}{3}493532 D4938234938\frac{2}{3}493832 Show answer & explanationCorrect answer: DExplanation423+4423+44423+444423=?=4×23+(4+44+444+4444)=83+4936=223+4936=4938234\frac{2}{3} + 44\frac{2}{3} + 444\frac{2}{3} + 4444\frac{2}{3} = ? \\[5pt] = 4 \times \frac{2}{3} + (4 + 44 + 444 + 4444) \\[5pt] = \frac{8}{3} + 4936 \\[5pt] = 2\frac{2}{3} + 4936 \\[5pt] = 4938\frac{2}{3}432+4432+44432+444432=?=4×32+(4+44+444+4444)=38+4936=232+4936=493832