SSC CHSL 2024 PYQ — Question 59

The correct answer is option 1 i.e. $\frac{853}{1610}$.

$\frac{4}{7}\times4\frac{1}{2}\div5\frac{1}{3}$ of $2\frac{1}{2}-\big(7\frac{7}{8}\div5\frac{1}{9}$ of $9\frac{9}{20}\big)+\frac{1}{2}$

⇒ $\frac{4}{7}\times\frac{9}{2}\div(\frac{16}{3}\times\frac{5}{2})-[\frac{63}{8}\div(\frac{46}{9}\times\frac{189}{20})]+\frac{1}{2}$

 ⇒ $\frac{4}{7}\times\frac{9}{2}\times\frac{3}{40}-[\frac{63}{8}\times\frac{10}{783}]+\frac{1}{2}$

⇒ $\frac{4}{7}\times\frac{9}{2}\times\frac{3}{40}-[\frac{63}{8}\times\frac{10}{783}]+\frac{1}{2}$

⇒ $\frac{27}{140}-\frac{105}{644}+\frac{1}{2}$

 ⇒ $\frac{27}{140}-\frac{105}{644}+\frac{1}{2}$

$\frac{621-525+1610}{3220}$

= 1706/3220

= 853/1610