SSC CGL 2024 PYQ — Question 57

The correct answer is Option 4 i.e. 1.

We know that,

sin(90 - θ) = cosθ

Now,

⇒ $3sin58^o\over{5cos32^o}$+ $2sin62^o\over{5cos28^o}$

⇒ $3sin(90-58)^o\over{5cos32^o}$ + $2sin(90-62)^o\over{5cos28^o}$

⇒ $3cos32^o\over{5cos32^o}$ + $2cos28^o\over{5cos28^o}$

⇒ ${3\over5} + {2\over5}$

⇒ $5\over5$ = 1