SSC CHSL 2025 PYQ — Question 69

SSC CHSL - 29 Nov 2025 - Shift 1 • Quantitative Aptitude • Q69

(3.57)2+(4.54)2+32.4156(4.54)2−(3.57)2=? \frac{(3.57)^2+(4.54)^2+32.4156}{(4.54)^2-(3.57)^2}=?

Show answer & explanation

Correct answer: A

Explanation

Has been given :

((3.57)² + (4.54)² + 32.4156) / ((4.54)² − (3.57)²

According to the formula:

a² + b² + 2ab = (a + b)²

b² − a² = (b − a)(b + a)

a = 3.57

b = 4.54

32.4156 = 2 × 3.57 × 4.54

Hence numerator = a² + b² + 2ab

= (a + b)²= (3.57 + 4.54)²= (8.11)²

Denominator= b² − a²

= (b − a)(b + a)= (4.54 − 3.57)(4.54 + 3.57)= 0.97 × 8.11

(8.11)² / (0.97 × 8.11)

= 8.11 / 0.97

= 8.36