SSC CGL 2023 PYQ — Question 57

The correct answer is Option 4 i.e. sin2A.

⇒ $\frac{2tanA}{1+tan^2A}=?$

⇒ $\frac{2sinA\over cosA}{1+{sin^2A\over cos^2A}}=?$

⇒ $\frac{2sinA\over cosA}{{cos^2A+sin^2A}\over cos^2A}=?$   [cos²A + sin²A = 1]

⇒ $\frac{2sinA\over cosA}{1\over cos^2A}=?$

⇒​​​​​​​ ${{2sinA\over cosA} }\times {cos^2A\over 1}=?$

⇒​​​​​​​​​​​​​​ ${2sinAcosA}=?$

⇒​​​​​​​ Sin2A = ?