₹21,000 is lent at compound interest of 10% p.a. for three years. Find the amount.
Show answer & explanation
Correct answer: B
Explanation
The correct answer is option 2 i.e. ₹27,951.
Amount = P(1 + R/100)n
= 21000(1 + 10/100)3
= 21000 × (110/100) × (110/100) × (110/100) = 27951