SSC CGL 2025 PYQ — Question 55

SSC CGL - 17 Sep 2025 - Shift 3 • Quantitative Aptitude • Q55

193+203−393+11819^3 + 20^3 - 39^3 + 118 is equal to:

Show answer & explanation

Correct answer: A

Explanation

The correct answer is option 1 i.e. -44342.

If a + b + c = 0, then a3 + b3 + c3 = 3abc

a = 19, b = 20, c = –39

a + b + c = 19 + 20 – 39 = 0

193 + 203 + (–39)3 = 3 × 19 × 20 × (–39) = –44460

So, 193 + 203 – 393 + 118 = –44460 + 118 = –44342