[(1 + p)(1 + p²)(1 + p)(1 + p)(1 + p¹6)(1 − p) − 1]
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e. -p32
[(1 + p)(1 + p²)(1 + p)(1 + p)(1 + p¹6)(1 − p) − 1]
(1 + p)(1 + p²)(1 + p)(1 + p)(1 + p¹)
This product looks like the expansion of (1 − p) minus (1 − p).
(1 − p)(1 + p) (1 + p²)(1 + p)(1 + p)(1 + p¹)
We can use the fact that the expression inside the brackets is equivalent to the following product:
(1 − p)
Subtract 1 from the result = (1 − p) - 1 = 1 - p - 1 = - p