(0.5)4−(0.4)4(0.5)2+(0.4)2=?\frac{(0.5)^4 - (0.4)^4}{(0.5)^2 + (0.4)^2} = ?(0.5)2+(0.4)2(0.5)4−(0.4)4=? A0.10 B0.12 C0.11 D0.09 Show answer & explanationCorrect answer: DExplanation(0.5)4−(0.4)4(0.5)2+(0.4)2a4−b4=(a2−b2)(a2+b2)((0.5)2−(0.4)2)((0.5)2+(0.4)2)(0.5)2+(0.4)2=(0.5)2−(0.4)2=0.25−0.16=0.09 \frac{(0.5)^4 - (0.4)^4}{(0.5)^2 + (0.4)^2} \\ a^4 - b^4 = (a^2 - b^2)(a^2 + b^2) \\ \frac{((0.5)^2 - (0.4)^2)((0.5)^2 + (0.4)^2)}{(0.5)^2 + (0.4)^2} \\ = (0.5)^2 - (0.4)^2 \\ = 0.25 - 0.16 \\ = 0.09(0.5)2+(0.4)2(0.5)4−(0.4)4a4−b4=(a2−b2)(a2+b2)(0.5)2+(0.4)2((0.5)2−(0.4)2)((0.5)2+(0.4)2)=(0.5)2−(0.4)2=0.25−0.16=0.09