SSC CGL 2026 PYQ — Question 6

SSC CGL Tier II - 19 Jan 2026 - Shift 1 • Quantitative Aptitude • Q6

0.1667×0.8333×0.33330.2222×0.6667×0.1250\frac{0.1667 \times 0.8333 \times 0.3333}{0.2222×0.6667×0.1250}  is approximately equal to:
 

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Correct answer: A

Explanation

The correct answer is Option 1 i.e. 2.5.

0.1667×0.8333×0.33330.2222×0.6667×0.1250\frac{0.1667 \times 0.8333 \times 0.3333}{0.2222×0.6667×0.1250}

=16×56×1329×23×18=\frac{{1\over6} \times {5\over6} \times {1\over3}}{{2\over9}×{2\over3}×{1\over8}}

= (5/108)/(1/54)

= (5/108) × 54

= 5/2

= 2.5